The steady-state gain of a 4-20 mA temperature transmitter with a span of 800 degrees Fahrenheit would be _______________.

To determine the steady-state gain of a 4-20 mA temperature transmitter with a span of 800 degrees Fahrenheit, it is necessary to understand how the gain is calculated in terms of the output current relative to the span of the measurement range.

The output current of a 4-20 mA transmitter corresponds to a specific range of the measured variable—in this case, temperature spanning from a minimum to a maximum value. The first step involves determining the total span: if the 4 mA output corresponds to the lowest temperature (let's say 0 degrees Fahrenheit for this example), then the 20 mA output would correspond to 800 degrees Fahrenheit (the maximum temperature). The span of the temperature measurement is therefore 800 degrees Fahrenheit.

The difference between the maximum and minimum output current gives a 16 mA range (20 mA - 4 mA), which corresponds to the full range of the measured variable (800 degrees Fahrenheit). The gain can be calculated by taking the output change (in mA) divided by the input change (in degrees).

Thus, the steady-state gain is calculated as follows:

Gain = (Output change) / (Input change) = (20 mA - 4 mA) /